How to compute a confidence interval for a population mean using z-scores (in Python, using SciPy)
Task
If we have a set of data that seems normally distributed, how can we compute a confidence interval for the mean? Assume we have some confidence level already chosen, such as $\alpha=0.05$.
We will use the normal distribution, which assumes either that we know the population standard deviation, or we have a large enough sample size (typically at least 30). If neither of these is true in your case, then you can use $t$-scores instead; see how to compute a confidence interval for a population mean.
Related tasks:
- How to compute a confidence interval for a population mean
- How to do a two-sided hypothesis test for a population mean
- How to do a two-sided hypothesis test for two sample means
- How to compute a confidence interval for a mean difference (matched pairs)
- How to compute a confidence interval for a regression coefficient
- How to compute a confidence interval for a single population variance
- How to compute a confidence interval for the difference between two means when both population variances are known
- How to compute a confidence interval for the difference between two means when population variances are unknown
- How to compute a confidence interval for the difference between two proportions
- How to compute a confidence interval for the expected value of a response variable
- How to compute a confidence interval for the population proportion
- How to compute a confidence interval for the ratio of two population variances
Solution
This solution uses a 95% confidence level, but you can change that in the
first line of code, by specifing a different alpha
.
When applying this technique, you would have a series of data values for which you needed to compute a confidence interval for the mean. But in order to provide code that runs independently, we create some fake data below. When using this code, replace our fake data with your real data.
We include the population standard deviation below, assuming it is known. See the notes at the end for what to do if you do not know the population standard deviation in your situation.
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
alpha = 0.05 # replace with your chosen alpha (here, a 95% confidence level)
pop_std = 250 # replace with your population standard devation, if known
data = [ 435,542,435,4,54,43,5,43,543,5,432,43,36,7,876,65,5 ] # fake
# We will use NumPy and SciPy to compute some of the statistics below.
import numpy as np
import scipy.stats as stats
# Compute the sample mean, as an estimate for the population mean.
sample_mean = np.mean( data )
# The margin of error then has the following formula.
z_score = stats.norm.ppf( 1 - alpha / 2 )
moe = pop_std * z_score / np.sqrt( len( data ) )
# The confidence interval is centered on the mean with moe as its radius:
( sample_mean - moe, sample_mean + moe )
1
(91.33619807845439, 329.0167430980162)
Notes:
- If you do not have the population standard deviation, but your sample is
large enough (typically at least 30), you can approximate the population
standard deviation with the sample standard deviation, using the code
std = stats.tstd( data )
. If your sample is not that large, then consider using a different technique instead; see how to compute a confidence interval for a population mean. - The solution above assumes that the population is normally distributed, which is a common assumption in introductory statistics courses, but we have not verified that assumption here.
Content last modified on 24 July 2023.
See a problem? Tell us or edit the source.
Contributed by Nathan Carter (ncarter@bentley.edu)